How many terms of ap 24 21 18 is 78

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Web20 nov. 2013 · Expert Answer a = 78, d = 71 - 78 = -7 Let n be the required no. of terms Sn = 465 [2a + (n - 1)d] = 465 n [156 + (n - 1) (-7)] = 930 7n 2 - 163n + 930 = 0 (7n - 93) (n - 10) = 0 n = or n = 10 Neglect n = as n cannot be a fraction No. of terms (n) = 10 Answered by 20 Nov, 2013, 02:39: AM Application Videos Web4 mrt. 2024 · How many Terms of the AP 24 21 18 must be taken so that their Sum is 78 Class 10 Maths Chapter 5 Example 13Example 13 : How many terms of the AP : 24, 21, ...

which terms of the AP: 21,18,15....is -78 - Brainly.in

Web25 short stories in several genres, all in the Life + 70 public domain, gathered from newspapers and magazines and in many cases republished here for the ... 18: The … Web24 + 21 + 18 + 15 = 78 — 3 A.. 24 + 21 = 45 B. 45 + 18 = 63 C. 78 - 63 = 15 63 + 15 = 78 CHECK More answers below R.N Singh Former Name R.N Singh at Educational … earth 2 economist

Which term of AP: 24,21,18......is -78?

Web3 apr. 2024 · First term (t 1) = a = 3, Common difference (d) = 8 – 3 = 5 and last term (t n) = 78 The general term of A.P is t n = a + (n - 1) d 78 = 3 + (n – 1)5 ⇒ 78 = 3 + 5n – 5 ⇒ 78 = - 2 + 5n ⇒ 78 + 2 = 5n ⇒ 80 = 5n ⇒ n = 16 ∴ 78 is 16th term of A.P: 3, 8,13, 18,... Download Solution PDF Share on Whatsapp Latest SSC CGL Updates Last updated on Apr 3, 2024 Web16 mrt. 2024 · Best answer Given A.P. 24, 21, 18,..... First term = 24 = a and common difference = – 3 = d ... (i) Let no. of terms is n. Sum of n terms = n 2 [2a + (n − 1)d] n 2 [ … WebConsider the following AP: 24, 21, 18..... How many terms of this AP must be taken so that their sum is 78? [4 MARKS] Solution Formula: 1 Mark Concept: 1 Mark Application: 2 … earth 2 earth

How many terms of the arithmetic sequence 24, 21, 18… must be …

Nth term of an AP(Arithmetic Progression): Formula and Sum of n Terms

WebWhen $$n=4,{s}_{4}=\dfrac{4}{2}\left[2\times 24+\left(4-1\right)\left(-3\right)\right]=2\left[48-9\right]=2\times 39=78$$ Web11 apr. 2024 · Complete step-by-step answer: The given A.P is 24, 21, 18,................... So the first term (a) of the A.P is = 24. And the common difference (d) of the A.P is ⇒ d = ( … earth 2 echoWeb29 jan. 2024 · Best answer Here, a = 24, d = 21 – 24 = –3, Sn = 78. We need to find n. Both values of n are admissible. So, the number of terms is either 4 or 13. ← Prev Question Next Question → Find MCQs & Mock Test JEE Main 2024 Test Series NEET Test Series Class 12 Chapterwise MCQ Test Class 11 Chapterwise Practice Test Class 10 Chapterwise … earth 2 episode order

"Web3 apr. 2024 · If the 10th term of an AP is 21 and 17th term is 8 more than the 13th term, then find the AP. Q4. How many terms of the AP 4, 11, 18, ________ will make the sum … " - How many terms of ap 24 21 18 is 78

How many terms of ap 24 21 18 is 78

How many terms of the A.P ; 24, 21, 18,... must be taken such that ...

Web14 aug. 2024 · Which term of AP 13 21 29 will be 48 less than its 19th term? ... How many terms of the arithmetic progression 24 21 18 must be taken so that their sum is 78? So … WebLet's check sum of 4 terms ⇒ a 4 = a 3 + d ⇒ a 4 = 18 + (-3) = 15 ∴ S 4 = 24 + 21 + 18 + 15 = 78. By formula, a n = a + (n - 1)d ⇒ a 5 = 24 + (5 - 1) (-3) ⇒ a 5 = 24 + 4 (-3) ⇒ a 5 = 24 - 12 = 12. a 6 = a 5 + d = 12 + (-3) = 9 a 7 = a 6 + d = 9 + (-3) = 6 a 8 = a 7 + d = 6 + (-3) = 3 a 9 = a 8 + d = 3 + (-3) = 0 a 10 = a 9 + d = 0 + (-3) = -3

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Web4 jan. 2024 · Given : AP = 24,21.. Sn = 78 . To find : n = ? AP = 24, 21 , 18 .. So, First term of AP = (a) = 24, common difference (d) = (21 - 24) = -3. Let n no. of terms to be taken, So that sum = 78. So, sum of n terms of the AP, Sn = n/2 × [2a + (n-1)d] Substituting the given value in above formula we get, = n/2 × (2 x 24 + (n-1) × (-3) ∴ n/2 × ... WebHow many terms of the a.p: 24,21,18,.must be taken so that the sum is 78? View answer. How many terms of the AP: 9,17,25 .must be taken to give a sum of 636? ... How many terms of an ap 45,39,33,.must be taken so thier sum is 180? for Class 10 2024 is part of Class 10 preparation.

WebEasy Solution Verified by Toppr Given, a=−6 d=− 211−(−6)= 21 Formula, S n= 2n[2a+(n−1)d] −25= 2n[2(−6)+(n−1) 21] −50=n[ 2−24+n−1] n 2−25n+100=0 (n−20)(n−5)=0 ∴n=5,20 Therefore the number of terms required is 5 or 20 Solve any question of Arithmetic Progression with:- Patterns of problems > Was this answer helpful? 0 0 Similar questions Web10 jul. 2024 · Click here 👆 to get an answer to your question ️ Howmanydermsmustofthe AP: 24, 21, 18....must be taken so that their sum is 78? shafiya15 shafiya15 10.07.2024 Math Secondary School answered How many derms must of the AP: 24, 21, 18.... must be taken so that their sum is 78? 1

Web19 apr. 2024 · So, the sum of the first 20 terms of the AP is 250. Example:How many terms of the AP: 24, 21, 18 … must be taken so that their sum is 78? Solution:Here, a = 24, d = 21 – 24 = –3, Sn= 78. We need to find n. We know that Sn= n/2[2a + (n – 1) d] Therefore, 78 = n/2[2 × 24 + (n – 1) × (-3)] 78 × 2 = n [48 – 3n + 3] 156 = 51n – 3n2 3n2– … WebConsider the following AP24 21 18How many terms of this AP must be taken so that their sum is 78 [4 MARKS] Formula 1 MarkConcept 1 MarkApplication 2 ... Consider the …

Web29 mrt. 2024 · Here, a = 24 d = 21 – 24 = –3 Also, given Sum = 78 Sn = 78 We have to find value of n Putting these values in equation Sum = 𝒏/𝟐 [𝟐𝒂+ (𝒏−𝟏)𝒅] 78 = 𝑛/2 [2×24+ (𝑛−1) (−3)] 78 …

WebHow many terms of the A.P. 24, 21, 18, … must be taken so that the sum is 78? Explain the double answer. Advertisement Remove all ads Solution A.P. is 24, 21, 18,... Sum = … earth 2 earth organicsWeb8 jan. 2024 · here,a = 24d = -3an = -78an = a + (n - 1)d -78 = 24 + (n - 1)-3 -78 = 24 -3n + 3 3n = 24 + 3 + 78 3n = 105 n = 105/3 n = 35so, -78 is 35th term of AP ctc homesWebLet the number of terms taken be n. THe given A.P is 24, 21, 18, ..... Here a = 24 and d = 21 - 24= -3 `S = n/2[2a + (n - 1)d]` `=> 78 = n/2 [2 xx 24 + (n - 1)xx (-3)]` ctc hondaWeb18 jun. 2016 · The simplest arithmetic progression satisfying the given condition is the constant progression with all $45$ terms equal to $18.$ The sum of that progression is … ct christmas expoWeb28 mrt. 2024 · Ex 5.3, 18 Important . Ex 5.3, 19 ... Ex 5.3, 4 - Chapter 5 Class 10 Arithmetic Progressions (Term 2) Last updated at March 28, 2024 by Teachoo. This video is only available for Teachoo black users Subscribe Now Get live Maths 1-on-1 Classs - Class 6 to 12. Book 30 minute class for ₹ 499 ₹ 299. ctc hotlineWeb14 mei 2024 · How many terms of the AP : 24, 21, 18, . . . must be taken so that their sum is 78? Q.38. How many terms of the AP : 9, 17, 25, . . . must be taken to give a sum of … ct choice voucher programWebHow many terms of the A.P: 24,21,18,.... must be taken so that their sum is 78? Medium Solution Verified by Toppr ⇒S n= 2n[2a+(n−1)d] ⇒78= 2n(2a+(n−1)d) ⇒78= 2n(2(24)+(n+1)(−3)) ⇒156=n(48−3n+3) ⇒156=n(51−3n) ⇒156=51n−3n 2 ⇒3n 2−51n+156=0 ⇒3n 2−12n−39n+156=0 ⇒3n(n−4)−3q(n−4)=0 ⇒n=4 or n= 339=13 Solve … earth 2 episode 1